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Leetcode

Leetcode - Reformat Date - my solution using javascript

Reformat Date.

Given a date string in the form Day Month Year, where:

  • Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
  • Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
  • Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

  • YYYY denotes the 4 digit year.
  • MM denotes the 2 digit month.
  • DD denotes the 2 digit day.

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

 

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

 

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

 

Constraints:

The given dates are guaranteed to be valid, so no error handling is necessary.

   

My solution:

/**
 * @param {string} date
 * @return {string}
 */
var reformatDate = function(date) {
    
    let dateAry = date.split(" ");
    
    let day = dateAry[0].match(/[0-9]+/gi)[0];
    
    day = day.padStart(2, '0');
    
    let month = '';
    
    switch(dateAry[1]) {
        case 'Jan': {
            month = '01';
            break;
        }
        case "Feb": {
            month = '02';
            break;
        }
        case 'Mar': {
            month = '03';
            break;
        }
        case 'Apr': {
            month = '04';
            break;
        }
        case 'May': {
            month = '05';
            break;
        }
        case 'Jun': {
            month = '06';
            break;
        }
        case 'Jul': {
            month = '07';
            break;
        }
        case 'Aug': {
            month = '08';
            break;
        }
        case 'Sep': {
            month = '09';
            break;
        }
        case 'Oct': {
            month = '10';
            break;
        }
        case 'Nov': {
            month = '11';
            break;
        }
        default: {
            month = '12';
            break;
        }
    }
    
    let year = dateAry[2];
    
    return `${year}-${month}-${day}`;
    
};